Optimal. Leaf size=140 \[ \frac {2}{3} a x^{3/2}+\frac {4 b x \text {ArcTan}\left (e^{c+d \sqrt {x}}\right )}{d}-\frac {4 i b \sqrt {x} \text {PolyLog}\left (2,-i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \sqrt {x} \text {PolyLog}\left (2,i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \text {PolyLog}\left (3,-i e^{c+d \sqrt {x}}\right )}{d^3}-\frac {4 i b \text {PolyLog}\left (3,i e^{c+d \sqrt {x}}\right )}{d^3} \]
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Rubi [A]
time = 0.09, antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {14, 5544,
4265, 2611, 2320, 6724} \begin {gather*} \frac {2}{3} a x^{3/2}+\frac {4 b x \text {ArcTan}\left (e^{c+d \sqrt {x}}\right )}{d}+\frac {4 i b \text {Li}_3\left (-i e^{c+d \sqrt {x}}\right )}{d^3}-\frac {4 i b \text {Li}_3\left (i e^{c+d \sqrt {x}}\right )}{d^3}-\frac {4 i b \sqrt {x} \text {Li}_2\left (-i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \sqrt {x} \text {Li}_2\left (i e^{c+d \sqrt {x}}\right )}{d^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 14
Rule 2320
Rule 2611
Rule 4265
Rule 5544
Rule 6724
Rubi steps
\begin {align*} \int \sqrt {x} \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right ) \, dx &=\int \left (a \sqrt {x}+b \sqrt {x} \text {sech}\left (c+d \sqrt {x}\right )\right ) \, dx\\ &=\frac {2}{3} a x^{3/2}+b \int \sqrt {x} \text {sech}\left (c+d \sqrt {x}\right ) \, dx\\ &=\frac {2}{3} a x^{3/2}+(2 b) \text {Subst}\left (\int x^2 \text {sech}(c+d x) \, dx,x,\sqrt {x}\right )\\ &=\frac {2}{3} a x^{3/2}+\frac {4 b x \tan ^{-1}\left (e^{c+d \sqrt {x}}\right )}{d}-\frac {(4 i b) \text {Subst}\left (\int x \log \left (1-i e^{c+d x}\right ) \, dx,x,\sqrt {x}\right )}{d}+\frac {(4 i b) \text {Subst}\left (\int x \log \left (1+i e^{c+d x}\right ) \, dx,x,\sqrt {x}\right )}{d}\\ &=\frac {2}{3} a x^{3/2}+\frac {4 b x \tan ^{-1}\left (e^{c+d \sqrt {x}}\right )}{d}-\frac {4 i b \sqrt {x} \text {Li}_2\left (-i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \sqrt {x} \text {Li}_2\left (i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {(4 i b) \text {Subst}\left (\int \text {Li}_2\left (-i e^{c+d x}\right ) \, dx,x,\sqrt {x}\right )}{d^2}-\frac {(4 i b) \text {Subst}\left (\int \text {Li}_2\left (i e^{c+d x}\right ) \, dx,x,\sqrt {x}\right )}{d^2}\\ &=\frac {2}{3} a x^{3/2}+\frac {4 b x \tan ^{-1}\left (e^{c+d \sqrt {x}}\right )}{d}-\frac {4 i b \sqrt {x} \text {Li}_2\left (-i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \sqrt {x} \text {Li}_2\left (i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {(4 i b) \text {Subst}\left (\int \frac {\text {Li}_2(-i x)}{x} \, dx,x,e^{c+d \sqrt {x}}\right )}{d^3}-\frac {(4 i b) \text {Subst}\left (\int \frac {\text {Li}_2(i x)}{x} \, dx,x,e^{c+d \sqrt {x}}\right )}{d^3}\\ &=\frac {2}{3} a x^{3/2}+\frac {4 b x \tan ^{-1}\left (e^{c+d \sqrt {x}}\right )}{d}-\frac {4 i b \sqrt {x} \text {Li}_2\left (-i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \sqrt {x} \text {Li}_2\left (i e^{c+d \sqrt {x}}\right )}{d^2}+\frac {4 i b \text {Li}_3\left (-i e^{c+d \sqrt {x}}\right )}{d^3}-\frac {4 i b \text {Li}_3\left (i e^{c+d \sqrt {x}}\right )}{d^3}\\ \end {align*}
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Mathematica [A]
time = 52.46, size = 172, normalized size = 1.23 \begin {gather*} \frac {2 \left (a d^3 x^{3/2}+3 i b d^2 x \log \left (1-i e^{c+d \sqrt {x}}\right )-3 i b d^2 x \log \left (1+i e^{c+d \sqrt {x}}\right )-6 i b d \sqrt {x} \text {PolyLog}\left (2,-i e^{c+d \sqrt {x}}\right )+6 i b d \sqrt {x} \text {PolyLog}\left (2,i e^{c+d \sqrt {x}}\right )+6 i b \text {PolyLog}\left (3,-i e^{c+d \sqrt {x}}\right )-6 i b \text {PolyLog}\left (3,i e^{c+d \sqrt {x}}\right )\right )}{3 d^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 2.21, size = 0, normalized size = 0.00 \[\int \left (a +b \,\mathrm {sech}\left (c +d \sqrt {x}\right )\right ) \sqrt {x}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {x} \left (a + b \operatorname {sech}{\left (c + d \sqrt {x} \right )}\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \sqrt {x}\,\left (a+\frac {b}{\mathrm {cosh}\left (c+d\,\sqrt {x}\right )}\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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